Okay I got this in Class should be easy enough to solve for you guys.

There is a moat that surronds a castle. The moat is a rectangle, there is a grass ledge on both sides of the moat. (Grass ledge demensions don't matter) The moat is more than 10 feet wide and it is equal on all sides. You have two 10 foot boards.

Question: How wide can the moat be and you still can get across with the boards? There is no way to join the boards together. And one cannot make a pyramid over the moat or put the boards in the water.

I know the solution to how to place the boards, but I can't figure out how to calculate the width.

Any Help? Thanks in advanced.

-Aaron

• How are you going to place the boards? - stormcrow - September 7, 2002 - 00:26 UTC
  • It's a me a Mario. - emperor__alikar - September 8, 2002 - 16:15 UTC
    • Solution - yanniru - September 9, 2002 - 01:15 UTC
      • Oops- please sub isosceles for equilateral - yanniru - September 9, 2002 - 01:30 UTC
        • Unfortunately, we both calculated WRONG - carefuluniverse - September 9, 2002 - 17:17 UTC
        • Should we have plugged the geometry into polynomial equations? - carefuluniverse - September 9, 2002 - 17:28 UTC
          • I forgot to include the width - yanniru - September 9, 2002 - 20:57 UTC
      • You proved the problem forgot the necessity of overlap - carefuluniverse - September 9, 2002 - 07:05 UTC
        • Overlap... - pmartin - September 9, 2002 - 22:07 UTC
          • Are you saying there's no need for boards to rest on the banks? - carefuluniverse - September 9, 2002 - 23:57 UTC
            • No - pmartin - September 10, 2002 - 04:54 UTC
              • I see...with my ears; I mean, with my eyes - carefuluniverse - September 11, 2002 - 15:16 UTC
• Ask a silly question...okay, the question is not quite silly - carefuluniverse - September 7, 2002 - 01:54 UTC
  • The ramp is attached to the motorcycle with just enough cord - carefuluniverse - September 9, 2002 - 17:19 UTC
• 10.6 feet - pmartin - September 7, 2002 - 04:47 UTC
  • Oops! That should be "go to the southeast corner" - pmartin - September 7, 2002 - 05:13 UTC
    • I'm sorry to say it, Paul, but that's not what he asked - kantolfir2 - September 7, 2002 - 07:32 UTC
      • I was not really "correcting" you... please pardon the tone - carefuluniverse - September 9, 2002 - 15:38 UTC
        • No problem - pmartin - September 9, 2002 - 16:04 UTC
          • "what the original question has to do with God and/or Science" - carefuluniverse - September 9, 2002 - 19:50 UTC
  • Paul is correct - luis_hamburgh - September 7, 2002 - 12:40 UTC
    • "Correct" is something a dog can be; give him a treat - carefuluniverse - September 7, 2002 - 14:40 UTC
      • that was "two" boards - kantolfir2 - September 7, 2002 - 16:02 UTC
    • But how do you cross it? - richard - September 11, 2002 - 16:19 UTC
      • Buy a helicopter - stormcrow - September 11, 2002 - 17:07 UTC
      • You guys are smart because you agree! - carefuluniverse - September 11, 2002 - 19:53 UTC
        • Well I wouldn't say that to that extent... - richard - September 11, 2002 - 21:22 UTC
          • real world - carefuluniverse - September 12, 2002 - 01:08 UTC
• Problem solving part two... - cosmosapiens - September 8, 2002 - 09:04 UTC
  • You're mean - luis_hamburgh - September 8, 2002 - 14:52 UTC
    • Lol! I figured you'd get it right away Luis! (nt) - cosmosapiens - September 8, 2002 - 23:31 UTC
  • Is my solution correct? - harvey1 - September 8, 2002 - 17:38 UTC
    • Another solution - harvey1 - September 8, 2002 - 23:30 UTC
      • More than four? Hmmm... that's a tough one ! - cosmosapiens - September 8, 2002 - 23:41 UTC
      • Harv, - luis_hamburgh - September 8, 2002 - 23:41 UTC
        • Oops - luis_hamburgh - September 8, 2002 - 23:53 UTC
        • That's right... - harvey1 - September 9, 2002 - 01:28 UTC