Back to Home

God & Science Forum Message

Forums: Atm · Astrophotography · Blackholes · Blackholes2 · CCD · Celestron · Domes · Education
Eyepieces · Meade · Misc. · God and Science · SETI · Software · UFO · XEphem
RSS Button

Home | Discussion Forums | God and Science | Post
Login

Be the first pioneers to continue the Astronomy Discussions at our new Astronomy meeting place...
The Space and Astronomy Agora
Solution

Forum List | Follow Ups | Post Message | Back to Thread Topics | In Response To
Posted by Richard Ruquist on September 9, 2002 01:15:15 UTC

Allow for a one foot overlap at any landing, where the first board lies on two same sides of the moat at a corner, and where the second board lies on the first board and on the inside corner of the moat.

The result forms a triangle of base 8 feet and of height 8 feet. Next to that triangle is an equilateral triangle, formed from the 8 foot base of the first board with the outer sides of the moat. The height of this triangle is 4 feet. That is the max distance of an 8 foot board from the outer sides is the 4 feet from the center of the board to the outer corner.

So now we know the total distance from the inner corner to the outer corner is 12 feet, the length of the usuable second board plus the distance to the outer corner.

That 12 foot path forms an equilateral triangle with the width of the moat, with 12 feet beingf the hypotenuse (Sp?). So the max width of the moat must be 12 devided by the square root of 2, or 6x1.414= 8.484

Follow Ups:

Login to Post
Additional Information
Google
 
Web www.astronomy.net
DayNightLine
About Astronomy Net | Advertise on Astronomy Net | Contact & Comments | Privacy Policy
Unless otherwise specified, web site content Copyright 1994-2022 John Huggins All Rights Reserved
Forum posts are Copyright their authors as specified in the heading above the post.
"dbHTML," "AstroGuide," "ASTRONOMY.NET" & "VA.NET"
are trademarks of John Huggins