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Posted by Joseph Roser on March 19, 2001 11:59:29 UTC

The process also works in weak gravity fields.

Whence the energy surplus? The hole's rotation is not affected and if the products of the beta decay reaction are blown away in a jet or simply leave ballistically then nothing ever crosses the event horizon. The hole's mass and rotation are unchanged yet there is still an energy surplus derived from the gravitational potential.

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