A basic model of a photon may be:
three categories juggled with two intersections linking them juggled;
split a photon:
you have to take two versions of the three categories and get two versions of their intersections; but the two versions of their intersections are still not exactly defined.
Using overlapped circles to draw this like Venn diagrams:
category A (or C) overlaps category B in overlap zone ab (or cb).
THEN ab (or cb) overlaps C (or A).
category B (or A) overlaps C in overlap zone bc (or ac).
THEN bc (or ac) overlaps A (or B).
category C (or B) overlaps A in overlap zone ca (or ba).
THEN ca (or ba) overlaps B (or C).
By splitting a photon: you have to split three options into two versions.
Perhaps "spin up/ down" is like knowing which version you have got; and "spin left/ right" is like knowing which version you haven't got?
If you know which version you've got; then the other photon must have the other versions (so you get up and down spin)(you have say first; middle, or last). The other photon has left /right spin (it has first+middle, or first+last; or middle+last).
If you know which version you haven't got, you know left and right? (as you must be left with first+middle, or first+last, or middle+last); the other photon must have that version you know you do not have at least (so is spun up/down ?)(so must have first, or middle, or last).
How do strings fit in?
Strings involve directionality, or stringiness; basically seem to be like number-lines.
Instead of 4-D space-time consider 4-D as: pattern, pattern, comparison, new comparison.
A,B; comparison C; new comparison D.
Six hidden dimensions?: A,B in C; A,B in D; C in D?
6 + 4 = 10 dimensions. Conservation of A and B in C and in D and in C,D would give an A-B string in 10 dimensions?
If left is past and right is future; and "weak force" involves rejuggling back in a pattern that was juggled out"; then weak force involves left polarization.
Conservation of an A-B string might require 4 dimensions distributed over 6 hidden so 4 x 6 = 24 dimensions; plus an A and a B dimension if futher conservation of string required to count it so get a string in 26 dimensions?
The fermion (unit meets group) could survive in 10 dimensions? (As unit A-B string just 4 + 6?) But the boson (group meets group) needs 26 dimensions? (As group A-B string needs A dimension, B dimension, + (6 x 4) dimensions?
Superbrane: distributing (A+B dimensions) over (4x6) dimensions to get 2-D sheets?
19 constants in physics standard model:
distribute (4+6) over (4+6) as one 4+6 overview say of 10 + 10 ; so = (20-1) = 19 constants?
take overview 4 of (4 x 4) to get "nuts" and "bolts" connected by uncertainties (Misner strings) as (6 x 6)?
6 hidden view of 4?
LOT OF GUESSING ABOVE