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Arguing With You Could Make Me Seem A Fool

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Posted by Michael W. Pearson on February 22, 2002 19:39:31 UTC

for spending the pixils

You are teasing again, as usual. Don't bother to deny it.
Stating by definitions:
A model, equation, or law can have "rigor" and not provide for all cases. It's not only "whether" it is rigorous or not, but "how" rigorous" and if you truly can object to that, you're not using your training or your mind.

What definition of rigor are YOU smoking
...I mean, using?


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