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Acceleration Of Gravity

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Posted by Greg Luton on January 21, 2003 04:52:47 UTC

I did not multiply the force of gravity by the units of energy.

I will put this in more familiar terms to show what I was doing.

F=Gmm/d^2=Newton's third law
F=ma (force equals mass times acceleration)
a=d/t^2 (acceleration equals distance per time interval squared)
is proportional to = (`)
m*d/t^2 (`) mm/d^2
Solve for mass:
d^3/t^2 (`) m (distance cubed per time interval squared is proportional to mass.

Do you understand? Do you understand what this means?

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