Back to Home

Blackholes Forum Message

Forums: Atm · Astrophotography · Blackholes · Blackholes2 · CCD · Celestron · Domes · Education
Eyepieces · Meade · Misc. · God and Science · SETI · Software · UFO · XEphem
RSS Button

Home | Discussion Forums | Blackholes I | Post
Login

Be the first pioneers to continue the Astronomy Discussions at our new Astronomy meeting place...
The Space and Astronomy Agora
Anti-Gravity

Forum List | Follow Ups | Post Message | Back to Thread Topics
Posted by Abhijit Brijlal Patil on March 29, 2002 09:33:19 UTC

Anti-Gravity
Mr. Abhijit Patil, C/o LIC of India, At/Po/Tq: Shahada City,
Dist: Nandurbar,(MS), INDIA. Pin:425409. Email: xabhix@hotmail.com

Abstract:

This Article propose model to create anti-gravity.

Introduction:

Sir Issac Newton observed that if we pick up particle and drop it, it falls straight down on planet. If we throw this particle, instead of dropping straight down on planet, it travels in space for some distance then falls down on planet taking parabolic path. He further observed that if we throw this particle with certain(critical) velocity, the particle will keep travelling, rotating around planet and will never fall on planet! But, in this case, to overcome gravity of planet, particle must revolve around planet. This article aims to propose model to keep a body at fixed position above planet without falling on planet.

Mathematical Model of Anti-Gravity:

G = Gravitational constant,
M = Mass of planet,
m = Mass of particle,
R = Radius of planet,
v = Velocity of particle,

As Newton explained beyond doubt through equations, kinetic energy(KE) of particle to escape from gravitational field of planet must be equal to gravitational potential energy of planet(U)

KE = (1/2)m*v^2 and U = GMm/R
As KE = U hence (1/2) m*v^2 = GMm/R
so v^2 = 2*G*M / R
i.e. v = (2GM/R)^(1/2)

Now we must note here that we are dealing here with only KE of particle.

If we take a circular ring and rotate it in vacuum with linear velocity v = (2GM/r)^(1/2), this ring will never fall on planet. It will keep rotating in vacuum forever. Because though the every particle of ring is rotating in definite space, still every particle in ring has linear velocity v and hence every particle has KE to counter gravitational potential energy(U) of planet. The ring will keep rotating in space where it is and gravity of planet will not act on ring. So planet will move in space but the ring will not.

Orbital(critical) velocity of particle revolving around planet is given by v = (GM/R)^(1/2)

So here also, as the particle has velocity v, we are dealing with KE of particle. Hence if we rotate the ring in vacuum with velocity v = (GM/R)^(1/2), it will keep rotating and never fall on planet, but still as the every particle in ring is under gravitational field of planet, ring will rotate with planet and at the same time move in space with planet. So the observer on planet will see the ring rotating at fixed position above the surface of planet forever. This ring will never fall on planet.

Conclusion:

We have Anti-Gravity.

Follow Ups:

Login to Post
Additional Information
Google
 
Web www.astronomy.net
DayNightLine
About Astronomy Net | Advertise on Astronomy Net | Contact & Comments | Privacy Policy
Unless otherwise specified, web site content Copyright 1994-2020 John Huggins All Rights Reserved
Forum posts are Copyright their authors as specified in the heading above the post.
"dbHTML," "AstroGuide," "ASTRONOMY.NET" & "VA.NET"
are trademarks of John Huggins