I wrote this in another forum:

masses of the quarks:

The book "A brief history of science. As seen through the development of scientific instruments" by James Crump; gives a "table of elementary particles" in the back.

From this I get the masses of the quarks as:

in Mev:

up: 5
down: 10

charm: 1600
strange: 180

top: 180,000
bottom; 4,500

If I take "electron volt" as "generalisation potential difference" and take the down quark as a unit:

I get mass ratios to downquark of:

(downquark: 1)
upquark: 1/2 of down

charm: 160 times down
strange: 15 times down

bottom: 450 times down
top: 1800 times down

I wonder if it can make sense?

Consider two blocks: which is up? which is down?

Need three blocks: to know which is up.

Need no more to know which is down but have two options:

either of the first two;

so mass of "up quark" is 1/2 that of down-quark?

How can you know which is bottom and which is down?

Maybe need four blocks?

then the bottom three can be divided into two different groups of "one" and "two".

Either of the three lower blocks could be "down"; if group the lowest three together then only have three groups so have ended out with bottom two as a single "down"?

Solve this by having five blocks: then have two ways of getting two lower blocks but one of these ways overlaps down (3rd block down).

Add another block to remove the overlap of the two bottom block-pair options say; but now have two pairs of lower blocks; one pair could be "down" and one pair could be "bottom" but which is which?

If multiply the six boxes now by 3: you get two ways the third block down can happen:
once as a single group; and once as a single block.

So this differentiates "down" from "bottom".

eV is electron potential difference:

translate to: generalisation potential difference

in base 10 gives 10,000 as "10 x 10" is "generalisation" (or base 10 view of "electron") and 1000 is the difference in potential from "x 3" when trying to create ONE difference between defining "bottom" and "top" quarks via base 10 expansion series via "potential" (re-distributing in base 10).

Have 3 x 6 = 18; x 10,000 = 180,000 as "every way quark/bottom can happen in base 10"?

BUT how know "top" from "bottom"?

Need one more block to give a "super 4" effect (the Hall effect?): this creates a point of difference between "bottom" and "top".

So arranging the blocks 8 in a row I draw a circle around the left two, then an arc around each one to their right; I also draw a circle around the right two and draw an arc around each two to their left.

Using "O" s as blocks:

(O(O)(O)(O)(O)(O)O)O)

boundaries of )( cancel leaving the first as 10x (as a base 10 building block say) and the last as a 10x but choose one of them as down and get x10 left.

The initial 3 x 6 boxes has become re-distributed by an extra multi-phase box to become two ways 3x6 can happen giving 3x3 with one way 6 cannot happen so is 5:

3x3 x 5 gives 45;

45 x 10 gives 450 times downquark mass for bottom quark.

(bit of guesswork here!)

Maybe to differentiate "quark" from "bottom quark" in base 10 the 180,000 mass of quark/bottom is diluted by "top" each way giving two x10 dilutions leaving bottom as unity and top as 1800 times mass of bottom?

Fractional distillation of quarks from a base 10 matrix?

Strange quark:

in a series of blocks might call "strange" quark one that is in two places at once (so two blocks surrounding a middle block.

How tell this quark apart from "down"?

Three groups of three boxes allows separation of the lowest group of three as either strange or down: this 3 plus other 6 if re-distributed in each other's space gives 3 x 6 mixing allowing a point of difference in defining their roles?

So get 18 x down quark for strange quark mass?

Once again "mass" appears to involve "many" and is associated with "curved space" that is two views of space that things can be mutually together in yet not collide.

By having many options they can be in harmonious co-existence in base10 matrix algebra say.

Charm quark:

suppose charm involves a box in the middle of two boxes each side:

How separate "down" from "charm"?

If have a row of six blocks can have two places after first place for being in the middle with a block each side and any of the four first blocks can be "down" so have two charm views of "down".

So if take the 4 down and x 4 gives 4 x 4 = 16 options to allow room for charm to be in the same universe but different dimension to down.

16 x one base10 difference in dimension gives 160 x down quark mass for charm quark.

This has been an attempt to fit around the given quark masses so may seem contrived but may work out as basic principles involving "base 10 space" "dimensions in base 10 space" and minimum definitions of mutual but distinct (differentiated) quark occupation of base 10 space.

-dolphin