Back to Home

God & Science Forum Message

Forums: Atm · Astrophotography · Blackholes · Blackholes2 · CCD · Celestron · Domes · Education
Eyepieces · Meade · Misc. · God and Science · SETI · Software · UFO · XEphem
RSS Button

Home | Discussion Forums | God and Science | Post
Login

Be the first pioneers to continue the Astronomy Discussions at our new Astronomy meeting place...
The Space and Astronomy Agora
Francis J. Mueller

Forum List | Follow Ups | Post Message | Back to Thread Topics | In Response To
Posted by Tim on November 30, 2003 02:22:18 UTC

author of Elements of Algebra says so.

quoting:
"Zero divisors are excluded because the resulting quotient would either be contradictory or indeterminant. An example of the first instance might be 7/0. If we represent the quotient as q, then 7/0 = q implies that q*0=7.
But every number, when multipied with 0, has 0 for the product; so 7 as the product for q*0 is impossible. A similar contradiction occurs for every other nonzero dividend and zero divisor.
When both the dividend and the divisor are zero, we have the case of 0/0 . This time let us call the would be quotient k. If 0/0 = k, then k*0=0 which is true for every number in the set that k might represent:
7*0=0, 12*0=0, 1/2*0=0, ect. This implies that 0/0=7, 0/0=12, 1/2/0=1/2 ect. The lack of a unique quotient when the divisor and the dividend are zero makes 0/0 indeterminant.
For these reasons, then, division by zero is excluded."

regards, tim

Follow Ups:

    Login to Post
    Additional Information
    Google
     
    Web www.astronomy.net
    DayNightLine
    About Astronomy Net | Advertise on Astronomy Net | Contact & Comments | Privacy Policy
    Unless otherwise specified, web site content Copyright 1994-2024 John Huggins All Rights Reserved
    Forum posts are Copyright their authors as specified in the heading above the post.
    "dbHTML," "AstroGuide," "ASTRONOMY.NET" & "VA.NET"
    are trademarks of John Huggins