No such thing as delta function eyes. It is merely a non-rigorous math function- non-rigorous because it is infinite. Its Fourier transform requires integration of F=1 times the exponential all the way from minus infinity to plus infinity. Those infinities are important. The F function cannot be arbitrary.


***"...the delta function must have the effect of making the integral over t dash receive zero contribution from all t dash except in the immediate neighbourhood of t dash = t, where the contribution is so large that a **************** **** finite **************** value for the integral results." ***

The problem with Dick is that he never used a value of tdash = t in his theory (t is where the delta function is non-zero). He avoided the instant t that you are describing.

Do you have a copy of his analysis? I can give you the specific equations where he set everything to zero.

Regards, Richard

• Just for now; to Yanniru - dolphin - July 6, 2002 - 05:54 UTC
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    • Hope to explain later - dolphin - July 11, 2002 - 07:59 UTC
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