Back to Home

God & Science Forum Message

Forums: Atm · Astrophotography · Blackholes · Blackholes2 · CCD · Celestron · Domes · Education
Eyepieces · Meade · Misc. · God and Science · SETI · Software · UFO · XEphem
RSS Button

Home | Discussion Forums | God and Science | Post

Be the first pioneers to continue the Astronomy Discussions at our new Astronomy meeting place...
The Space and Astronomy Agora
The Local Radial Velocity Of A Freefalling..

Forum List | Follow Ups | Post Message | Back to Thread Topics | In Response To
Posted by Bruce on June 18, 2002 02:40:03 UTC

object is simply

dr/dTau = dr(shell)/dt(shell) = - (2M/r)^1/2

M(Earth)= .00888meter

You'll notice that at r(Earth) it is the escape velocity ~ 11,175m/s [if the atmosphere was nonexistant].

At r = 2M [the event horizon] the radial velocity for a freefalling object is c.

Follow Ups:

Login to Post
Additional Information
About Astronomy Net | Advertise on Astronomy Net | Contact & Comments | Privacy Policy
Unless otherwise specified, web site content Copyright 1994-2024 John Huggins All Rights Reserved
Forum posts are Copyright their authors as specified in the heading above the post.
"dbHTML," "AstroGuide," "ASTRONOMY.NET" & "VA.NET"
are trademarks of John Huggins