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| But, Which Is More Fundamental?
Forum List | Follow Ups | Post Message | Back to Thread Topics | In Response To Posted by Harvey on November 24, 2001 00:29:54 UTC |
For example, in Newtonian physics -ma + F = 0, however in QM this expression corresponds to a quantum operator which cannot equal to the zero operator. However, the average values of this quantum operator are zero. Isn't the path integral more fundamental then the Newton derivative in that case? The path integral sums over the respective action S thereby making Newtonian physics possible.
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