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FineS137@aol.com

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Posted by FineS137 on April 13, 2001 19:12:34 UTC

The first thing I have to say about this is that whether the particle intercats with a nucleus or not, the actual result does not defy conservation of energy. Yes, according to a local frame the particle is blue shifted as is falls closer to the hole, and at a lower position can hypothetically interact weakly to produce other particles that are massive, but the gravitational mass "of the system" as observed remotely would actually be the same at this point in the particles motion whether or not it has done this weak interaction process.

Second, For such a particle in free fall, conservation of energy is not desribed by
KE + PE = E = constant,
however there is a
kinetic energy parameter + effective potential = energy parameter = constant
wich does result in the same kind of a conservation equation. I just carefully distinguish it because these energy parameters are not equivalent to their true energy counterparts.

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