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 Be the first pioneers to continue the Astronomy Discussions at our new Astronomy meeting place...The Space and Astronomy Agora Re: Tidal Forces For Those Into The Math Forum List | Follow Ups | Post Message | Back to Thread Topics | In Response ToPosted by Zephram Cochrane/">Zephram Cochrane on October 19, 1999 06:31:52 UTC

...For instance take the tidal acceleration near the event horizon of a black hole given by Da = 16p3GLMh/C3 at the following web sight Black hole equations. This is most easily derived by taking a gradient with respect to "remote frame coordinates" of the proper acceleration. Thus L is a remote frame length...

I figured I'd prove that using L as a remote frame length from how I said the tidal acceleration could be derived is results in their equation. I'll start with: a = -GMh/r2

da/dr = 2GMh/r3 r is a remote coordinate frame length so going to a finite small remote coordinate frame length L this becomes

Da/L = 2GMh/r3

Da = 2GLMh/r3

Da = 16p3GLMh/(8p3r3)

Da = 16p3GLMh/(2pr)3

Da = 16p3GLMh/C3