Blackholes2 Forum Message | |
| Forums: |
Atm ·
Astrophotography ·
Blackholes ·
Blackholes2 ·
CCD ·
Celestron ·
Domes ·
Education
Eyepieces · Meade · Misc. · God and Science · SETI · Software · UFO · XEphem |
|
|
|
|
||||
|
|
||||||
Be the first pioneers to continue the Astronomy Discussions at our new Astronomy meeting place... The Space and Astronomy Agora |
| Re: Tidal Forces For Those Into The Math
Forum List | Follow Ups | Post Message | Back to Thread Topics | In Response To Posted by Zephram Cochrane/">Zephram Cochrane on October 19, 1999 06:31:52 UTC |
...For instance take the tidal acceleration near the event horizon of a black hole given by Da = 16p3GLMh/C3 at the following web sight Black hole equations. This is most easily derived by taking a gradient with respect to "remote frame coordinates" of the proper acceleration. Thus L is a remote frame length... I figured I'd prove that using L as a remote frame length from how I said the tidal acceleration could be derived is results in their equation. I'll start with: a = -GMh/r2 da/dr = 2GMh/r3 r is a remote coordinate frame length so going to a finite small remote coordinate frame length L this becomes Da/L = 2GMh/r3 Da = 2GLMh/r3 Da = 16p3GLMh/(8p3r3) Da = 16p3GLMh/(2pr)3 Da = 16p3GLMh/C3
|
|
|
| Additional Information |
|---|
 |
| About Astronomy Net | Advertise on Astronomy Net | Contact & Comments | Privacy Policy |
|
Unless otherwise specified, web site content Copyright 1994-2024 John Huggins All Rights Reserved Forum posts are Copyright their authors as specified in the heading above the post. "dbHTML," "AstroGuide," "ASTRONOMY.NET" & "VA.NET" are trademarks of John Huggins |