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Time Vs Energy

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Posted by Abhijit Brijlal Patil on February 27, 2002 13:41:11 UTC

TIME VS ENERGY
Mr. Abhijit B Patil, C/o Life Insurance Corporation of India, At/Po/Tq: Shahada City,
Dist: Nandurbar, Maharastra State, INDIA. Pin: 425 409. E-Mail Address: xabhix@hotmail.com
Homepage: http://www.geocities.com/discoverynews

Introduction:

When we OPEN the valve of garden hose, with hose full of water, water begins to flow out. Established knowledge of fluid dynamics states that this information travels across full length of hose pipe back to water level in reservoir through pressure waves with appropriate acoustic velocity in hose pipe. When these pressure waves reach to water level in reservoir, only after that water level comes down. This is not true. If it is true, then we can use this time interval of information transfer to create "free" energy.

Mathematical Model of Fluid Flow:
Consider a reservoir of full of fluid. Let height of fluid level in this reservoir from earth surface be h. Inlet A of horizontal pipe of length L is attached to bottom of reservoir. At outlet B, there is vertical empty pipe of height H and volume U. Let H = h + x where H > h. So height of vertical pipe i.e. "H" is greater than height of fluid level in reservoir i.e. "h". Let a be cross sectional area of horizontal pipe of length L and b that of vertical pipe of height H. Let b < a. So cross sectional area "b"of vertical pipe is less than cross sectional area "a" of horizontal pipe. Let c be velocity of propagation of pressure waves in pipe. Let t be time taken for these pressure waves to reach to inlet A from outlet B. Let U be volume and v be average velocity of fluid entering in horizontal pipe during time interval t.

Hence t = (L / c) i.e. L = ct ...................Equn. (1)
U = avt = bH where b < a .......... ...................Equn. (2)
H = h + x where H > h .............................Equn. (3)

At time T = 0, fluid is flowing in system of reservoir and entire horizontal pipe of length L. At time T = 0, outlet B of horizontal pipe is connected to vertical empty pipe of height H so that flow of fluid in horizontal pipe is directed in upward direction in vertical pipe.

This information regarding change in situation i.e. pressure change at outlet B will travel through pressure waves with acoustic velocity c and reaches to inlet A after time interval t. But fluid flowing in inlet A has no information about situation change at outlet B during this time interval t, hence U volume of fluid will flow in inlet A during this time interval t. After time t, system of horizontal pipe and vertical pipe is isolated.

At time T = 0, entire horizontal pipe of length L was full of flowing water. After time T = t, U volume of fluid has entered in closed pipe system of horizontal pipe of length L and vertical pipe of height H. Hence only way to accommodate this U volume of fluid is vertical pipe of height H. Hence there will U volume of fluid in vertical pipe of height H after time t.

Let d be density of this fluid. Hence mass of fluid of volume U, m = Ud.

(1) At time T = 0, when this fluid of mass m was in reservoir at height h, its potential energy, PE = mgh.
(2) At time T = t, when this fluid of mass m is in vertical pipe of height H, its potential energy, PE = mgH.

But H = h + x and H > h
hence mgH = mg(h + x) = mgh + mgx
i.e. mgH > mgh

Only force acting on fluid in system is Gravity. There is no other force present in system. Then where from this extra PE equal to "mgx" came?

Query:

Consider isolated vertical pipe full of water. water begins to flow out when valve at lower end is opened. Established knowledge of fluid dynamics state that this information travels upwards with appropriate acoustic velocity(about 1482 m/s) in pipe through pressure waves i.e. longitudinal waves of compression and rarefaction. water level comes down only when pressure waves reaches to upper water level.

Consider that temperature of water is decreased so that ice rod is formed in this vertical pipe. Let A be lower end of this ice rod and B be upper end. Valve is removed so that ice rod comes down freely due to gravity. Explanation of superluminal transmission of information states that this information motion of lower end A will travels to upper end B through rod with through electromagnetic waves.

When temperature of water(or any fluid) in pipe is decreased, then PRECISELY at what water temperature this mode of transfer of information changes from pressure waves(longitudinal waves, speed 1482 m/s) to electromagnetic waves (transverse waves, speed < 299792428 m/s)?

Conclusion:

After carefully studying the mathematical model of fluid flow, we should come to the conclusion that information regarding uninterrupted, free, flow of fluid under gravitational field must travel back to fluid level in reservoir at exactly same moment. Otherwise law of conservation of energy is violated.

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