Its simple to understand how Newton would do it and more difficult to understand the GR derivation which renders the same resultant.
Newton
GMm/r=1/2mv^2
v^2=2GM/r
Since the event horizon is where the escape velocity would be c substitute c^2 for v^2.
r=2GM/c^2
It works out that r=2M when you express mass M in geometric units.
The curvature at r=2M is infinite as reckoned from the far away observer perspective
drshell=dr/(1-2M/r)^1/2
The local shell observer takes the integral of the above expression to show the distance r=2M+dr to r=2M is finite.
Where the curvature goes to infinite is at the singularity. GR can't describe these physics because the description for the singularity requires a marriage of quantum physics and relativity. This is what string theory (quantum gravity)is all about.

• Re: Re: Rayon of Schwarschild - post-ein - January 8, 2001 - 04:56 UTC
  • Correction for an oversight - post-ein - January 8, 2001 - 05:09 UTC
    • Did it again - post-ein - January 8, 2001 - 05:11 UTC
      • If you don't succeed at first... - post-ein - January 8, 2001 - 05:17 UTC
• More on Relativistic Event Horizon - post-ein - January 9, 2001 - 04:37 UTC
  • Apparently you have a copy of Hakim? - bruce - January 9, 2001 - 07:05 UTC
    • By the book! - jim_b - January 9, 2001 - 10:00 UTC
      • About 50 years ago - bruce - January 10, 2001 - 05:33 UTC
        • Both E's are numerically the same - jim_b - January 10, 2001 - 10:39 UTC
          • A possible objection - jim_b - January 10, 2001 - 21:45 UTC