"After converting mass to a length (1 kilogram equals 7.424x10^-28 meter/kilogram)" - Bruce

That doesn't make sense.

Your equation: 1 kg = 7.424e-28 m/1 kg
If you multiply both sides by 1 kg you get:
1 kg^2 = 7.424e-28 m

how does kg^2 = m?
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Taking the derivative of a gravity function (an acceleration function) gives you its "jolt," also known as the rate of change of the acceleration.
You are taking the derivative of the acceleration with respect to the radius (displacement from the center of mass) of an object. Unless an object is very rapidly gaining mass (and therefore increasing its gravity), the acceleration due to gravity of the mass will not increase. Therefore, the gravity is a constant and the derivative with respect to the radius would equal zero.

• Re: Re: Re: One aspect of Einstein's theory - bruce - November 27, 2000 - 20:33 UTC
  • Exploring Black Holes, Edwin Taylor and John Archibald Wheeler - bruce - November 27, 2000 - 20:42 UTC
  • Correction - bruce - November 28, 2000 - 04:17 UTC
  • Re: Re: Re: Re: One aspect of Einstein's theory - bladesinger - November 30, 2000 - 19:23 UTC
    • Re: Re: Re: Re: Re: One aspect of Einstein's theory - bruce - November 30, 2000 - 21:13 UTC
      • Professor Edwin Taylor's and Wheeler's vision. - bruce - November 30, 2000 - 21:18 UTC