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 Be the first pioneers to continue the Astronomy Discussions at our new Astronomy meeting place...The Space and Astronomy Agora Re: Re: One Aspect Of Einstein's Theory Forum List | Follow Ups | Post Message | Back to Thread Topics | In Response ToPosted by Michael Wright on November 27, 2000 18:05:43 UTC

"After converting mass to a length (1 kilogram equals 7.424x10^-28 meter/kilogram)" - Bruce

That doesn't make sense.

Your equation: 1 kg = 7.424e-28 m/1 kg
If you multiply both sides by 1 kg you get:
1 kg^2 = 7.424e-28 m

how does kg^2 = m?
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Taking the derivative of a gravity function (an acceleration function) gives you its "jolt," also known as the rate of change of the acceleration.
You are taking the derivative of the acceleration with respect to the radius (displacement from the center of mass) of an object. Unless an object is very rapidly gaining mass (and therefore increasing its gravity), the acceleration due to gravity of the mass will not increase. Therefore, the gravity is a constant and the derivative with respect to the radius would equal zero.

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